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Topic: How to calculate length of array? (Read 447 times) |
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Endymion
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How to calculate length of array?
« Thread started on: May 21st, 2012, 1:42pm » |
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Sometimes I need to pass arrays by value, not by reference. So, I want to create tool for cloning arrays. My code not work:
Code: def proc_CloneArray(Array#(), return ArrayClone#())
local ArrayLength% = len(Array#()) *| just idea illustration
dim ArrayClone#(ArrayLength%)
ArrayClone#() = Array#()
endproc
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| « Last Edit: May 21st, 2012, 1:44pm by Endymion » |
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I wanted to do something. I wanted to do something as badly as a genie who's been let out of his bottle for the first time in a thousand years. Anything at all: Raise up castles, lay waste cities, program in Basic, or embroider in cross-stitch. -- Nochnoy Dozor (The Night Watch) By Sergei Lukyanenko
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admin
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Re: How to calculate length of array?
« Reply #1 on: May 22nd, 2012, 08:04am » |
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on May 21st, 2012, 1:42pm, Endymion wrote:| Sometimes I need to pass arrays by value, not by reference. So, I want to create tool for cloning arrays. |
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This code works:
Code: DEF PROC_CloneArray(Array#(), RETURN ArrayClone#())
LOCAL ArrayLength%
ArrayLength% = DIM(Array#(),1)
DIM ArrayClone#(ArrayLength%)
ArrayClone#() = Array#()
ENDPROC
Can I recommend that you don't use the *| style of commenting routinely, since that sort of comment is preserved in a compiled EXE and wastes space:
http://bb4w.wikispaces.com/Alternative+comment+styles
Richard.
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Endymion
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Re: How to calculate length of array?
« Reply #2 on: May 22nd, 2012, 08:51am » |
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on May 22nd, 2012, 08:04am, Richard Russell wrote:
Thanks!
Quote:| Can I recommend that you don't use the *| style of commenting routinely, since that sort of comment is preserved in a compiled EXE and wastes space: |
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OK.
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I wanted to do something. I wanted to do something as badly as a genie who's been let out of his bottle for the first time in a thousand years. Anything at all: Raise up castles, lay waste cities, program in Basic, or embroider in cross-stitch. -- Nochnoy Dozor (The Night Watch) By Sergei Lukyanenko
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