The first line assumes a new level is required. The program then inspects each AlienXAlive flag in turn and if this alien is still alive, resets the NewLevel flag to false. If it completes its checks and the flag is still true, all the aliens must be dead so line 'em up and start again. Question: what happens if there are 40 aliens? Or 100? Using this method, that's a lot of lines of code. There must be a better way:
REM ... NewLevel=TRUE : REM Assume new level IF Alien1Alive THEN NewLevel=FALSE IF Alien2Alive THEN NewLevel=FALSE IF Alien3Alive THEN NewLevel=FALSE IF NewLevel THEN REM setup new level ENDIF REM ...
The first thing is the keyword DIM. DIM stands for DIMension and is an instruction to the computer to set aside an area of memory for an array variable. You tell BASIC how many variables the array holds in the brackets after the name. In this case, we are telling the computer we have 50 aliens, so reserve 50 locations, one for each. Previously, we have let BASIC define our variables when first used, but an array is different. By defining the size of an array, BASIC can perform a check each time it is used in code. If we try to access outside the array, BASIC will tell you by halting the program and producing a friendly message (i.e. it crashes). Although not compulsory, it is good practice to declare all arrays at the top of the program. This puts them all together in one place and gets all the memory allocations out of the way when the program starts up.
DIM AlienAlive(50) REM ... NewLevel=TRUE : REM Assume new level FOR I%=1 TO 50 IF AlienAlive(I%) THEN NewLevel=FALSE NEXT I% IF NewLevel THEN REM setup new level ENDIF REM ...
Once declared, we can use the array pretty much as we do any other variable, each individual element is accessed by specifying its number: AlienAlive(1), AlienAlive(39) or as in the line IF AlienAlive(I%) ... using the counter in a FOR loop to decide which element we wish to inspect. By using this method, we can check as many aliens as we wish all in the same number of lines of code.
Here is a complete example which stores grades for a number of pupils and then does something with the data:
Make room for 100 pupils if you want by changing the relevant lines, but you might get bored entering all that data!
REM Student grade program DIM Grade%(5) REM First, collect the data FOR I%=1 TO 5 PRINT "Enter grade for student ";I%;": "; INPUT Grade%(I%) NEXT I% REM Work out the average Total%=0 FOR I%=1 TO 5 Total%=Total%+Grade%(I%) NEXT I% REM Print the average PRINT "The average grade was ";Total%/5 REM Find the minimum grade Minimum%=999 FOR I%=1 TO 5 IF Grade%(I%)<Minimum% THEN Minimum%=Grade%(I%) ENDIF NEXT I% REM Print the minimum PRINT "The minimum grade was ";Minimum% END
BBC BASIC actually gives you an extra element, so when you declare
Grade%(5) you get 6 elements: Grade%(0) to Grade%(5). In practice, it's
often easier to ignore the first element because it's human nature to
think in terms of pupil 1, pupil 2 etc, not pupil 0. But it's there if
you want it. All the elements of an array are set to 0, or empty in
case of strings, on declaration and once declared, you can't resize the
array by re-declaring it later on. It may help to think of an array as
a collection of boxes, so if we entered values for the above students
of 40,80,60,70 and 55, this is how they would be stored:
Element | 0 | 1 | 2 | 3 | 4 | 5 |
Value | 0 | 40 | 80 | 60 | 70 | 55 |
This would define a grid 6 cells by 6 cells (remember element 0). This is how it would look in our box diagram:
DIM Grid%(5,5)
0 | 1 | 2 | 3 | 4 | 5 | |
0 | ||||||
1 | ||||||
2 | ||||||
3 | ||||||
4 | ||||||
5 |
You can define an array with 3 dimensions:
If you think of a two dimensional grid as a page, we've just declared 11 pages, each containing a grid 11 elements square. If you're working with the demo version, arrays are a superb way to run out of memory. Think about it, there are 11*11*11 = 1331 elements in this array, so just be wary before getting too carried way. Realistically, unlike some other BASICs, with BBC BASIC you can declare as many dimensions as you want, but in practice programmers rarely use more than 3.
DIM Grid%(10,10,10)
Initialising Arrays
READ, DATA and RESTORE
Arrays can be used to hold data, but one of the problems is getting the data into the array. In the grade program above, entering is fine because every time you run it, you would probably want to enter different values. Consider this:
Sort of defeats the object really, doesn't it? BASIC, of course, has got there before us and provides a way to set up variables and arrays that are going to be the same each time.
REM Days in a month DIM Month%(12) REM First, collect the data FOR I%=1 TO 12 PRINT "Enter days in month ";I%;": "; INPUT Month%(I%) NEXT I% REM Now ask for month INPUT "Enter month number: " M% PRINT "Month ";M%;" has ";Month%(M%);" days." END
That's much better. There are a pair of keywords here, READ and DATA. DATA contains just that, a collection of data, numeric or string that can be used in the program. What the data is and the order you put it is entirely up to you. When the program encounters a READ statement, it goes off and finds the next DATA statement. It then reads the value back into the variable given, a little like INPUT. BASIC remembers where it got up to, so the next time it encounters READ, it carries on from where it left off.
REM Days in a month DIM Month%(12) REM First, collect the data FOR I%=1 TO 12 READ Month%(I%) NEXT I% REM Now ask for month INPUT "Enter month number: " M% PRINT "Month ";M%;" has ";Month%(M%);" days." END DATA 31,28,31,30,31,30,31,31,30,31,30,31
Obviously, there should be as many pieces of data as there are READ instructions (including the number of times READ is called in a loop) or the program gets upset. You are not constrained to using READ only with arrays, it is perfectly acceptable to set single variables using this method, but with a loop it is possible to initialise an array with very few lines of code.
DATA statements can be split in any way you choose, for example, we could have written:
or even:
DATA 31,28,31,30,31 DATA 30,31,31,30,31 DATA 30,31
You're the programmer, it's up to you, just make sure that there are as many items as there are READs.
DATA 31 DATA 28 DATA 31 DATA 30 DATA 31 DATA 30 DATA 31 DATA 31 DATA 30 DATA 31 DATA 30 DATA 31
You can mix and match items as long as you read the correct type into the correct variable.
DATA statements can be placed anywhere in the program, BASIC will just ignore them until told to use them. They are usually placed at the bottom of the program after END so they don't clutter the code, with the exception given below.
REM Days in a month DIM Month%(12), Name$(12) REM First, collect the data FOR I%=1 TO 12 READ Month%(I%) READ Name$(I%) NEXT I% REM Now ask for month INPUT "Enter month number: " M% PRINT Name$(M%);" has ";Month%(M%);" days." END DATA 31,January,28,February,31,March DATA 30,April,31,May,30,June DATA 31,July,31,August,30,September DATA 31,October,30,November,31,December
There are occasions when it is necessary to reread a set of data. Suppose you had a default set of values which could be reset from an option in a menu. To force the data pointer back to a specific place, we use the RESTORE command. RESTORE has a few options, the first has no argument and resets the data pointer to the first DATA statement in the program.
Another use is to specify a line number. (Line numbers are discussed in Appendix A. If you're not familiar with them, the general consensus these days is that you are not missing much but might like to zip off there and give them a glance.) Using RESTORE with a line number will reset the data pointer to the first item on the line given. This can be useful for specifying alternate sets of data.
The line number can be calculated if required.
10 REM Months in English and French 20 DIM Month$(12) 30 REM First, collect the data 40 INPUT "Do you want French? (y/n) " Ans$ 50 IF Ans$="N" OR Ans$="n" THEN 60 RESTORE 170 70 ELSE 80 RESTORE 210 90 ENDIF 100 FOR I%=1 TO 12 110 READ Month$(I%) 120 NEXT I% 130 REM Now ask for month 140 INPUT "Enter month number: " M% 150 PRINT "Month ";M%;" is ";Month$(M%) 160 END 170 DATA January,February,March 180 DATA April,May,June 190 DATA July,August,September 200 DATA October,November,December 210 DATA Janvier,Fevrier,Mars 220 DATA Avril,Mai,Juin 230 DATA Juillet,Aout,Septembre 240 DATA Octobre,Novembre,Decembre
To remove the line numbers, RESTORE gives us yet another option. In this we specify an offset from the line containing the RESTORE instruction (NOT the line with the first DATA statement). The number given tells BASIC the number of lines to move forward from the current position. To indicate that we are using an offset and not a line number, the number must be preceded by a +. Here is the above program without line numbers using this method. Examine the numbers in the RESTORE lines and count forwards to see where each one points to.
You can only go forwards here, try specifying a negative offset and BASIC will complain. Lines here are actual physical lines, including blank ones and REMs, not just those containing code. As can be seen, if the program was to be extended, we could easily lose track of the offsets and create chaos. Perhaps this method is best employed when the DATA is close to the RESTORE statements.
REM Months in English and French DIM Month$(12) REM First, collect the data INPUT "Do you want French? (y/n) " Ans$ IF Ans$="N" OR Ans$="n" THEN RESTORE +11 ELSE RESTORE +13 ENDIF FOR I%=1 TO 12 READ Month$(I%) NEXT I% REM Now ask for month INPUT "Enter month number: " M% PRINT "Month ";M%;" is ";Month$(M%) END DATA January,February,March DATA April,May,June DATA July,August,September DATA October,November,December DATA Janvier,Fevrier,Mars DATA Avril,Mai,Juin DATA Juillet,Aout,Septembre DATA Octobre,Novembre,Decembre
In any of the above methods, if there is no data at the line given by RESTORE, BASIC finds the next line that contains DATA and uses that instead.
REM ... IF Ans$="N" OR Ans$="n" THEN RESTORE +4 ELSE RESTORE +6 ENDIF DATA January,February,March DATA April,May,June DATA July,August,September DATA October,November,December DATA Janvier,Fevrier,Mars DATA Avril,Mai,Juin DATA Juillet,Aout,Septembre DATA Octobre,Novembre,Decembre
Initializing without READ and DATA
It is possible to initialize an array directly in code. This saves DATA and READ statements and is more in keeping with the way languages like C do this sort of thing. The first example initializes all the elements after the array has been declared. Don't forget that MyArray%(3) has 4 elements 0 to 3 so we need 4 values.
This can be done at anytime, not just when the array has been declared.
REM Inline initialization DIM MyArray%(3) MyArray%() = 1,2,3,4 FOR I%=0 TO 3 PRINT MyArray%(I%) NEXT I% END
If you supply less than the number of elements, only the given number are initialized.
REM Inline initialization DIM MyArray%(3) MyArray%() = 1,2,3,4 FOR I%=0 TO 3 PRINT MyArray%(I%) NEXT I% MyArray%() = 5,6,7,8 FOR I%=0 TO 3 PRINT MyArray%(I%) NEXT I% END
However, and this is really useful, you can preset an entire array if only one value is given. Great for initializing big arrays.
REM Initialize the first three elements DIM MyArray%(3) MyArray%() = 1,2,3 FOR I%=0 TO 3 PRINT MyArray%(I%) NEXT I% END
Multi-dimensional arrays are not a problem, as long as you get the order correct: right to left. In the example, the line has been split. This is not a problem, but you must still include a comma at the end of the split line, just as you would if it was continuous.
REM Set each element to 50 DIM MyArray%(100) MyArray%() = 55 FOR I%=0 TO 100 PRINT MyArray%(I%) NEXT I% END
Did somebody say strings? You can do these as well, but then, you'd expect that.
REM Initializing a multi-dimensional array DIM MyArray%(2,3) MyArray%() = 1,2,3,4,10,20,30, \ \ 40,100,200,300,400 FOR I%=0 TO 2 FOR J%=0 TO 3 PRINT MyArray%(I%,J%) NEXT J% NEXT I% END
When do you use inline and not READ/DATA? It's completely up to you. One of the advantages of the inline method is that it gets round the dreaded line number dependency when using RESTORE. On the other hand, if you have large amounts of DATA, then you may prefer to keep it from clogging up the body of the code.
REM Initializing a string array DIM Month$(12) Month$() = "","January","February", \ \ "March","April","May","June", \ \ "July","August","September", \ \ "October","November","December" FOR I%=1 TO 12 PRINT Month$(I%) NEXT I% END
Finding the size of an array
The DIM statement can be used as a function. It can have one or two arguments passed to it. The first parameter is always the name of the array. When used with just the name, DIM will respond with the number of dimensions of the array.
As previously stated, it is possible to have an array name which is the same as a variable so we use the array name followed by the empty brackets to distinguish it from an ordinary variable.
REM Finding the size of an array DIM Array1D(10) DIM Array2D(10,9) DIM Array3D(10,9,8) PRINT "Array","Dimensions" PRINT "Array1D",DIM(Array1D()) PRINT "Array2D",DIM(Array2D()) PRINT "Array3D",DIM(Array3D()) END
Once you know the number of dimensions, it is possible to ask DIM for the size of each by passing the particular dimension number as the second parameter.
To combine the above two, we can now find the number of dimensions and the size of each one.
REM Finding the size of an array DIM Array3D(10,9,8) PRINT "Dimension 2 has "; \ \ DIM(Array3D(),2);" elements." END
We'll mention this use of DIM again in the section on procedures and functions which is coming up soon, whereupon you will be able to see why we would want to do this. Until then, just bear it in mind.
REM Finding the size of an array DIM Array3D(10,9,8) N%=DIM(Array3D()) FOR I%=1 TO N% PRINT "Dimension:";N%; PRINT " Elements:";DIM(Array3D(),I%) NEXT I% END
Exercise
Here are the figures for the first six months' sales of triple fruit chocolate covered syrup and treacle flavour ice lollies from one local newsagent:
January 105
February 261
March 482
April 195
May
347
June
626
Set an array to hold these values. Then add to the program so it loops
through the values to find and print:
a) the month number for the lowest sales;
b) the month for the highest sales;
c) the total sales.
You can use the same FOR loop to achieve all three or do them
separately: your choice.
Modify the program to have an array of month names, initialize it and adapt the above program to display real names for the months.
CONTENTS |
CHAPTER 15 |